First, I have been through many very heavy SR threads over the last four years on BAUT and over that time I have finally figured out ALL the 'double speak' and true inconsistencies that make SR "Not Real"
IE: not even wrong.
The whole set up is all fatally flawed, especially the initial part of 'swapping' motions where one observer can be considered at rest and the other in opposite motion.
Are you trying to pull some trick with the accelerations? There are caveats in SR with accelerations, accelerating reference frames in particular. The plain old transformations are for the constant velocity pieces. For accelerating reference frames, see here.
IF observer B stops, fly's slower or speeds up, at a constant speed to infinity, it has absolutely nothing what-so-ever to do with observer A's motion!!!
There is NO 'light in it's own frame' that exists at all
Russ,
You said:
if one observer "A" is considered at rest when another observer "B" is moving away at .8c......then if "B" stops/is considered at rest, then "A" is moving away from "B" at .8c.
This cannot be correct. If B moves away from A at .8C relative to A, and then B stops relative to A, then both A and B are at rest relative to one another. I don't know where you get the idea that if B stops relative to A, then B will think/perceive that A is still moving. This is all relative motion, Russ, so your scenario fails.
- Mike Petersen
The chances that you have found something really easy that everyone else has somehow missed is small.
...which is another reason that I understand that ALL singularities MUST be eliminated to be talking about something "REAL"!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
And all those exclamation marks, you notice? Five? A sure sign of someone who wears his underpants on his head.
SR's definitions are based on a Singularity/division by 0...
Russ,
You said:
"cannot be 'swapped'"
which is a new word, not included in:
"if one observer "A" is considered at rest when another observer "B" is moving away at .8c......then if "B" stops/is considered at rest, then "A" is moving away from "B" at .8c."
You seem to like wriggling out of your own contradictions by changing what you said without acknowledging the fact. I believe I shall no longer post replies to your nonsense. Have a nice life. Oh, and by the way, you may have the last word, so have fun trashing me.
- Mike Petersen
Well, if you want to talk black holes :) That's open season, as far as I'm concerned, because folks still don't agree on their characteristics and genesis up to this very day.
The purpose of the paper of Einstein and Rosen was not to promote faster-than-light or inter-universe travel, but to attempt to explain fundamental particles like electrons as space-tunnels threaded by electric lines of force.
For folks who figure that supermassive black holes helped galaxies form, like the folks in our thread here, there is still a giant "well, where did they come from?" question
My armchair philosopher objection to black holes as pictures is that General Relativity's interaction between gravity and time, being equivalent to that between acceleration and time, would make time stand still at any event horizon, so how would it grow?
but I'm also no fan of GR's Equivalence Principle, where gravity is indistinguishable from acceleration.
No, that's GR, from which singularity math is derived. SR is based merely on a constant c in all velocity frames.
Change your experiment. Just before launch, give each of the twins in the rockets an injection that will keep them knocked out for 1 minute. When they wake up they're in a rocket. When they wake up they have no idea if the rocket is moving, or not. They're weightless, and might as well consider themselves to be at rest. How would they know they're moving? They "slept" through the launch. Each individual twin in his individual rocket can consider his rocket to be at rest, and look out the window and see 9 moving rockets and one moving planet. Each twin in the rocket will see the planet moving away with a different speed.
But, this post from Slang, clearly shows the opposite speed and direction of motion of observer A, when you 'stop' the traveling observer B when B has been traveling away from A. Now B is stopped/at rest, and A is traveling away from B at the same constant speed that B had been traveling at.
Sorry Ritchie...but the error in eqivocation is once again, with all the politeness I can muster, yours.
IF you eliminate 'acceleration' to get to 'Constant Velocity', then you cannot have the rockets fire their thrusters (for an equal amount of time) to come to "Rest"/stop.
IF a rocket/spaceship, with its observer B inside, is considered to be instantly traveling at 'a constant velocity' of .8c away from observer A, then, according to SR, B can be considered to be 'at rest', with A traveling away from B at .8c.
RussT said:
IF a rocket/spaceship, with its observer B inside, is considered to be instantly traveling (No acceleration) at 'a constant velocity' of .8c away from observer A, then, according to SR, B can be considered to be 'at rest' (stopped, with no deceleration), with A traveling away from B at .8c.
Either observer can consider himself to be 'at rest'/stopped and the other the one in motion....simple as that.Either observer can consider himself to be 'at rest'/stopped and the other the one in motion....simple as that.
Then you are saying something utterly unsurprising and non-contradictory to either SR or plain inertial frames.
Originally Posted by pzkpfw
Moderator
This has struck me quite strongly.
It seems...
From the point of view of light, it takes zero time to "get" from anywhere to anywhere, because, as far as any light in the Universe is concerned the distance between any two points is zero.
That is, as far as light is concerned, the entire Universe may as well all be in one place.
(A singularity?)
Since a singularity is a place where an equation gets a divide by zero error, yes, it is a singularity.
Then you are saying something utterly unsurprising and non-contradictory to either SR or plain inertial frames.
The ship is assumed to get to 'constant inertial speed' instantly and come to rest instantly
By the way, in this thread I am trying to show that light from SNe cannot get here in 0 time...which it most certainly cannot ;)
Changing reference frames, B will now be considered as going the negative vectored velocity that A was.
Ritchie, sorry but this is not making sense to me...A was stationary/at rest on earth, when B took off at 0.8c....so why are you saying...velocity that A was
Originally Posted by RussT
tusenfem...
Please re-open my new navigation with relativity thread.
If you re-read that thread, it is NOT me that is confused!
Everyone else is making conflicting and varying remarks about how SR works, even some who are supposed to be very knowledgable...especially Northern Boy.
I only have so much time to keep the most coherent ones straight...like grav was by far the best.
As to the ATM claim...it is absolutely obvious, that when one SR observer is considered 'at rest' with the other in 'inertial motion' at the same velocity, that they cann't even see which way to correctly go to get back to where their original destination is "Now"
I am sorry but I see no reason to open it again, unless you come with some real insight. You seem to think that SR does something magically when changing inertial frames. Even in this reply you come up with something that absolutely makes no sense:
that when one SR observer is considered 'at rest' with the other in 'inertial motion' at the same velocity
How is this supposed to be interpreted?
one SR observer is considered "at rest", well you don't say with respect to what, but that is not important, but ANY inertial observer can consider herself to be "at rest" and everything else moving.
Then you come with "another in 'inertial motion' at the same speed. What is that supposed to mean? same speed as WHAT? The first observer? than it is AT REST with respect to the first observer. Or whatever you mean.
Thus unless you can express yourself well, and try to finally understand relativity and Galilean relativity etc. etc. there is nothing to discuss. The reason why everyone is all over you is because your writing up of stuff is done hastily, unchecked, un proof read etc. You may think it is clear, but with the above example I hope it is clear that what you say is all but clear to anyone else who is reading it.
I stand by my decision. You are welcome to contact another mod. I will copy this message into the mod discussion session, so the others know what I said, and they may or may not agree with me.
That spaceship traveling, at any speed, will NOT make the observer on the Earth change his trajectory/orbit around the Sun, in any way what-so-ever!
Is that the source of your misunderstanding? That if you hold the spaceship as 'at rest', that somehow only the one other thing in your example changes relative velocity?
in post 2010-02-17 16:49
RussT said:
Either observer can consider himself to be 'at rest'/stopped and the other the one in motion....simple as that.
Then you are saying something utterly unsurprising and non-contradictory to either SR or plain inertial frames.
Try it like this...
A ship "B" takes off from the North Pole, straight up, nearly instantly at 'constant speed', at 0.9c, and is considered, nearly instantly, 'at rest' 2 seconds later...
What motion does the observer on earth "A", watching the take off, now have?
BUT, guys, this is just your basic SR...if one observer "A" is considered at rest when another observer "B" is moving away at .8c......then if "B" stops/is considered at rest, then "A" is moving away from "B" at .8c.
If observer "A", who started at rest on earth becomes the 'traveler', because "B" stops/is now concidered at rest, then observer "B" sees observer "A" on the earth, moving directly away from him at .8c.
Wow, thanks for taking the time to make that graphic Ritchie. However, I have absolutely NO CLUE as to why you have a third Rocket in the scenario ;(
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